Trigonometry Guide for the NESA Maths Syllabus

Trigonometry is an important topic in the NESA Mathematics syllabus for NSW high school students. This guide explains SOH CAH TOA for right-angled triangles, the sine, cosine and tangent ratios, the cosine rule, the area rule, and the CAST rule for the four quadrants. It is designed to help students understand formulas, choose the correct method, and practise exam-style trigonometry questions.
Trigonometry study graphic showing the Law of Sines, Cosine Rule, area of a triangle formula and CAST rule for NSW Year 9 and Year 10 maths students.

Table of Contents

Interactive maths practice

Trigonometry Practice Questions: NSW Year 9–10

This quiz covers the five main trigonometry skills students need for Year 9 and Year 10 maths practice. Each section has 10 questions with answers and working.

  • Year 9: Right-Angled Triangles and SOH CAH TOA
  • Year 9: The Law of Sines, also called the Sine Rule
  • Year 10: The Cosine Rule
  • Year 10: Area of a Triangle Using Trigonometry
  • Year 10: The Four Quadrants and the CAST Rule
  • 5 progressive levels
  • 50 practice questions
  • Instant answer checks
  • KaTeX-ready full working
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Level 1 Right-Angled Triangles and SOH CAH TOA 10 questions · Year 9 0/10

Tip: Identify the opposite, adjacent and hypotenuse sides before choosing sine, cosine or tangent. Enter numbers only; units and degree symbols are optional.
  1. A ladder is 5 m long and makes an angle of 60° with the ground. How high up the wall does it reach? Give your answer to 1 decimal place.

    View hint and full working

    Hint: Use sine because the height is opposite and the ladder is the hypotenuse.

    Working
    sin 60° = h ÷ 5
    h = 5 × sin 60°
    h ≈ 4.3 m
    Answer: 4.3 m
  2. A right-angled triangle has a hypotenuse of 13 cm and an adjacent side of 5 cm. Find cos θ to 3 decimal places.

    View hint and full working

    Hint: Cosine uses adjacent over hypotenuse.

    Working
    cos θ = adjacent ÷ hypotenuse
    cos θ = 5 ÷ 13
    cos θ ≈ 0.385
    Answer: 0.385
  3. A ramp rises 1.5 m over a horizontal distance of 6 m. Find the angle the ramp makes with the ground to 1 decimal place.

    View hint and full working

    Hint: Use tangent because the opposite and adjacent sides are given.

    Working
    tan θ = 1.5 ÷ 6
    tan θ = 0.25
    θ = tan⁻¹(0.25)
    θ ≈ 14.0°
    Answer: 14.0°
  4. A student stands 20 m from a tree. The angle of elevation to the top of the tree is 35°. Find the height of the tree to 1 decimal place.

    View hint and full working

    Hint: Use tangent because the height is opposite and the horizontal distance is adjacent.

    Working
    tan 35° = h ÷ 20
    h = 20 × tan 35°
    h ≈ 14.0 m
    Answer: 14.0 m
  5. A right triangle has an angle of 42° and an adjacent side of 9 cm. Find the hypotenuse to 1 decimal place.

    View hint and full working

    Hint: Use cosine because the adjacent side and hypotenuse are involved.

    Working
    cos 42° = 9 ÷ c
    c = 9 ÷ cos 42°
    c ≈ 12.1 cm
    Answer: 12.1 cm
  6. A kite is flying on a 30 m string. The string makes an angle of 50° with the ground. Find the height of the kite to 1 decimal place.

    View hint and full working

    Hint: Use sine because the height is opposite and the string is the hypotenuse.

    Working
    sin 50° = h ÷ 30
    h = 30 × sin 50°
    h ≈ 23.0 m
    Answer: 23.0 m
  7. A right triangle has an opposite side of 8 cm and an adjacent side of 15 cm. Find the angle θ to 1 decimal place.

    View hint and full working

    Hint: Use tangent because the opposite and adjacent sides are given.

    Working
    tan θ = 8 ÷ 15
    θ = tan⁻¹(8 ÷ 15)
    θ ≈ 28.1°
    Answer: 28.1°
  8. A 10 m ladder reaches 8 m up a wall. Find the angle the ladder makes with the ground to 1 decimal place.

    View hint and full working

    Hint: Use sine because the height is opposite and the ladder is the hypotenuse.

    Working
    sin θ = 8 ÷ 10
    sin θ = 0.8
    θ = sin⁻¹(0.8)
    θ ≈ 53.1°
    Answer: 53.1°
  9. A right triangle has a hypotenuse of 25 cm and an angle of 37°. Find the adjacent side to 1 decimal place.

    View hint and full working

    Hint: Use cosine because the adjacent side and hypotenuse are involved.

    Working
    cos 37° = a ÷ 25
    a = 25 × cos 37°
    a ≈ 20.0 cm
    Answer: 20.0 cm
  10. From the top of a 12 m building, the angle of depression to a car is 28°. Find the horizontal distance from the car to the building to 1 decimal place.

    View hint and full working

    Hint: The angle of depression equals the angle of elevation. Use tangent.

    Working
    tan 28° = 12 ÷ d
    d = 12 ÷ tan 28°
    d ≈ 22.6 m
    Answer: 22.6 m

Level 2 The Sine Rule 10 questions · Year 9 0/10

Tip: Match each side with its opposite angle. For SSA questions, check whether a second valid angle is possible.
  1. In triangle ABC, A = 40°, B = 65°, and a = 12 cm. Find b to 1 decimal place.

    View hint and full working

    Hint: Use the Sine Rule because a side and its opposite angle are known.

    Working
    a ÷ sin A = b ÷ sin B
    12 ÷ sin 40° = b ÷ sin 65°
    b = 12 × sin 65° ÷ sin 40°
    b ≈ 16.9 cm
    Answer: 16.9 cm
  2. A surveyor measures triangle ABC. Angle A = 52°, angle B = 71°, and side a = 18 m. Find side b to 1 decimal place.

    View hint and full working

    Hint: Use the Sine Rule and match each side with its opposite angle.

    Working
    18 ÷ sin 52° = b ÷ sin 71°
    b = 18 × sin 71° ÷ sin 52°
    b ≈ 21.6 m
    Answer: 21.6 m
  3. In triangle ABC, A = 35°, a = 9 cm, and B = 80°. Find b to 1 decimal place.

    View hint and full working

    Hint: Use the Sine Rule.

    Working
    9 ÷ sin 35° = b ÷ sin 80°
    b = 9 × sin 80° ÷ sin 35°
    b ≈ 15.5 cm
    Answer: 15.5 cm
  4. A triangle has A = 48°, a = 14 km, and b = 17 km. Find angle B to 1 decimal place.

    View hint and full working

    Hint: This is an ambiguous SSA case, so check both possible angles.

    Working
    sin B = b × sin A ÷ a
    sin B = 17 × sin 48° ÷ 14
    B₁ ≈ 64.5°
    B₂ = 180° − 64.5° ≈ 115.5°
    Both angles produce a valid triangle because A + B is less than 180° in each case.
    Answer: 64.5° or 115.5°
  5. Two rescue points form a triangle with a boat. A = 42°, B = 75°, and side a = 120 m. Find side b to 1 decimal place.

    View hint and full working

    Hint: Use the Sine Rule.

    Working
    120 ÷ sin 42° = b ÷ sin 75°
    b = 120 × sin 75° ÷ sin 42°
    b ≈ 173.2 m
    Answer: 173.2 m
  6. In triangle ABC, A = 55°, B = 35°, and a = 20 cm. Find b to 1 decimal place.

    View hint and full working

    Hint: Use the Sine Rule.

    Working
    20 ÷ sin 55° = b ÷ sin 35°
    b = 20 × sin 35° ÷ sin 55°
    b ≈ 14.0 cm
    Answer: 14.0 cm
  7. A triangular garden has A = 62°, B = 46°, and side a = 11 m. Find side b to 1 decimal place.

    View hint and full working

    Hint: Use the Sine Rule.

    Working
    11 ÷ sin 62° = b ÷ sin 46°
    b = 11 × sin 46° ÷ sin 62°
    b ≈ 9.0 m
    Answer: 9.0 m
  8. In triangle ABC, A = 30°, a = 8 cm, and b = 12 cm. Find angle B to 1 decimal place.

    View hint and full working

    Hint: This is an ambiguous SSA case, so check both possible angles.

    Working
    sin B = b × sin A ÷ a
    sin B = 12 × sin 30° ÷ 8 = 0.75
    B₁ = sin⁻¹(0.75) ≈ 48.6°
    B₂ = 180° − 48.6° ≈ 131.4°
    Both angles produce a valid triangle because A + B is less than 180° in each case.
    Answer: 48.6° or 131.4°
  9. A triangle has A = 70°, B = 40°, and a = 25 cm. Find side b to 1 decimal place.

    View hint and full working

    Hint: Use the Sine Rule.

    Working
    25 ÷ sin 70° = b ÷ sin 40°
    b = 25 × sin 40° ÷ sin 70°
    b ≈ 17.1 cm
    Answer: 17.1 cm
  10. A non-right triangle has A = 38°, B = 82°, and side b = 19 m. Find side a to 1 decimal place.

    View hint and full working

    Hint: Use the Sine Rule.

    Working
    a ÷ sin 38° = 19 ÷ sin 82°
    a = 19 × sin 38° ÷ sin 82°
    a ≈ 11.8 m
    Answer: 11.8 m

Level 3 The Cosine Rule 10 questions · Year 10 0/10

Tip: Use the Cosine Rule for two sides and the included angle, or for all three sides when finding an angle.
  1. A triangle has sides a = 7 cm and b = 9 cm with included angle C = 60°. Find side c to 1 decimal place.

    View hint and full working

    Hint: Use the Cosine Rule for two sides and the included angle.

    Working
    c² = a² + b² − 2ab cos C
    c² = 7² + 9² − 2(7)(9)cos 60°
    c² = 67
    c ≈ 8.2 cm
    Answer: 8.2 cm
  2. Two paths from a park entrance are 40 m and 55 m long. The angle between them is 70°. Find the distance between the two path ends to 1 decimal place.

    View hint and full working

    Hint: Use the Cosine Rule because two sides and the included angle are known.

    Working
    c² = 40² + 55² − 2(40)(55)cos 70°
    c² ≈ 3120.1
    c ≈ 55.9 m
    Answer: 55.9 m
  3. A triangle has sides 8 cm, 11 cm and 13 cm. Find the angle opposite the 13 cm side to 1 decimal place.

    View hint and full working

    Hint: Use the rearranged Cosine Rule.

    Working
    13² = 8² + 11² − 2(8)(11)cos C
    169 = 185 − 176 cos C
    cos C = 16 ÷ 176
    C ≈ 84.8°
    Answer: 84.8°
  4. A triangle has sides a = 10 m and b = 14 m with included angle C = 45°. Find side c to 1 decimal place.

    View hint and full working

    Hint: Use the Cosine Rule.

    Working
    c² = 10² + 14² − 2(10)(14)cos 45°
    c² ≈ 98.0
    c ≈ 9.9 m
    Answer: 9.9 m
  5. A triangular field has two sides of 120 m and 95 m with an included angle of 52°. Find the third side to 1 decimal place.

    View hint and full working

    Hint: Use the Cosine Rule.

    Working
    c² = 120² + 95² − 2(120)(95)cos 52°
    c² ≈ 9387.9
    c ≈ 96.9 m
    Answer: 96.9 m
  6. A triangle has sides 6 cm, 8 cm and 10 cm. Find the angle opposite the 10 cm side.

    View hint and full working

    Hint: Use the Cosine Rule. This is also a 6–8–10 right triangle.

    Working
    10² = 6² + 8² − 2(6)(8)cos C
    100 = 100 − 96 cos C
    cos C = 0
    C = 90°
    Answer: 90°
  7. Two boats leave the same dock. One travels 18 km and the other travels 25 km. The angle between their paths is 110°. Find the distance between the boats to 1 decimal place.

    View hint and full working

    Hint: Use the Cosine Rule.

    Working
    c² = 18² + 25² − 2(18)(25)cos 110°
    c² ≈ 1256.8
    c ≈ 35.5 km
    Answer: 35.5 km
  8. A triangle has sides 9 cm, 12 cm and 15 cm. Find the angle opposite the 15 cm side.

    View hint and full working

    Hint: This is a 9–12–15 right triangle, and the Cosine Rule confirms it.

    Working
    15² = 9² + 12² − 2(9)(12)cos C
    225 = 225 − 216 cos C
    cos C = 0
    C = 90°
    Answer: 90°
  9. A triangle has sides a = 13 cm and b = 16 cm with included angle C = 38°. Find side c to 1 decimal place.

    View hint and full working

    Hint: Use the Cosine Rule.

    Working
    c² = 13² + 16² − 2(13)(16)cos 38°
    c² ≈ 97.2
    c ≈ 9.9 cm
    Answer: 9.9 cm
  10. A triangle has sides 10 cm, 12 cm and 14 cm. Find the angle opposite the 14 cm side to 1 decimal place.

    View hint and full working

    Hint: Use the rearranged Cosine Rule.

    Working
    14² = 10² + 12² − 2(10)(12)cos C
    196 = 244 − 240 cos C
    cos C = 0.2
    C ≈ 78.5°
    Answer: 78.5°

Level 4 Area of a Triangle Using Trigonometry 10 questions · Year 10 0/10

Tip: Use A = ½ab sin C when two sides and their included angle are known.
  1. A triangle has sides 8 cm and 12 cm with included angle 45°. Find the area to 1 decimal place.

    View hint and full working

    Hint: Use the trigonometric area formula.

    Working
    A = ½ab sin C
    A = ½(8)(12)sin 45°
    A ≈ 33.9 cm²
    Answer: 33.9 cm²
  2. A triangular garden has two sides of 15 m and 20 m with an included angle of 60°. Find the area to 1 decimal place.

    View hint and full working

    Hint: Use A = ½ab sin C.

    Working
    A = ½(15)(20)sin 60°
    A ≈ 129.9 m²
    Answer: 129.9 m²
  3. A sail is triangular with sides 5 m and 7 m enclosing an angle of 50°. Find the area to 1 decimal place.

    View hint and full working

    Hint: Use the area rule with two sides and the included angle.

    Working
    A = ½(5)(7)sin 50°
    A ≈ 13.4 m²
    Answer: 13.4 m²
  4. A triangle has sides 10 cm and 16 cm with included angle 30°. Find the area.

    View hint and full working

    Hint: Use the trigonometric area formula.

    Working
    A = ½(10)(16)sin 30°
    A = 80 × 0.5
    A = 40 cm²
    Answer: 40 cm²
  5. A triangular park has two sides of 42 m and 35 m with an included angle of 72°. Find the area to 1 decimal place.

    View hint and full working

    Hint: Use the trigonometric area formula.

    Working
    A = ½(42)(35)sin 72°
    A ≈ 699.0 m²
    Answer: 699.0 m²
  6. A triangle has sides 9 cm and 11 cm with included angle 80°. Find the area to 1 decimal place.

    View hint and full working

    Hint: Use the trigonometric area formula.

    Working
    A = ½(9)(11)sin 80°
    A ≈ 48.7 cm²
    Answer: 48.7 cm²
  7. A roof panel is triangular. Two sides are 6 m and 9 m, and the included angle is 40°. Find the area to 1 decimal place.

    View hint and full working

    Hint: Use A = ½ab sin C.

    Working
    A = ½(6)(9)sin 40°
    A ≈ 17.4 m²
    Answer: 17.4 m²
  8. A triangle has sides 18 cm and 22 cm with included angle 105°. Find the area to 1 decimal place.

    View hint and full working

    Hint: Use the trigonometric area formula.

    Working
    A = ½(18)(22)sin 105°
    A ≈ 191.3 cm²
    Answer: 191.3 cm²
  9. A triangular shade cloth has sides 3.5 m and 4.2 m with included angle 65°. Find the area to 1 decimal place.

    View hint and full working

    Hint: Use the trigonometric area formula.

    Working
    A = ½(3.5)(4.2)sin 65°
    A ≈ 6.7 m²
    Answer: 6.7 m²
  10. A triangle has sides 24 cm and 30 cm with included angle 120°. Find the area to 1 decimal place.

    View hint and full working

    Hint: Use the trigonometric area formula.

    Working
    A = ½(24)(30)sin 120°
    A ≈ 311.8 cm²
    Answer: 311.8 cm²

Level 5 The Four Quadrants and CAST Rule 10 questions · Year 10 0/10

Tip: Use CAST: All ratios are positive in Quadrant 1, sine in Quadrant 2, tangent in Quadrant 3 and cosine in Quadrant 4.
  1. Which trigonometric ratio is positive in Quadrant 2: sine, cosine or tangent?

    View hint and full working

    Hint: In Quadrant 2, only sine is positive.

    Working
    CAST rule:
    Quadrant 1: All
    Quadrant 2: Sine
    Quadrant 3: Tangent
    Quadrant 4: Cosine
    Answer: sine
  2. Which quadrant contains an angle of 210°?

    View hint and full working

    Hint: 210° is between 180° and 270°.

    Working
    180° < 210° < 270°
    Therefore, 210° is in Quadrant 3.
    Answer: Quadrant 3
  3. Is cos 120° positive or negative?

    View hint and full working

    Hint: 120° is in Quadrant 2, where cosine is negative.

    Working
    120° is in Quadrant 2.
    In Quadrant 2, sine is positive and cosine is negative.
    Answer: negative
  4. Is tan 240° positive or negative?

    View hint and full working

    Hint: 240° is in Quadrant 3, where tangent is positive.

    Working
    240° is in Quadrant 3.
    In Quadrant 3, tangent is positive.
    Answer: positive
  5. A bearing of 135° lies in which quadrant if drawn on a standard four-quadrant diagram?

    View hint and full working

    Hint: 135° is between 90° and 180°.

    Working
    90° < 135° < 180°
    Therefore, 135° is in Quadrant 2.
    Answer: Quadrant 2
  6. Which trigonometric ratio is positive in Quadrant 4?

    View hint and full working

    Hint: In Quadrant 4, only cosine is positive.

    Working
    CAST rule:
    Quadrant 1: All
    Quadrant 2: Sine
    Quadrant 3: Tangent
    Quadrant 4: Cosine
    Answer: cosine
  7. Find the reference angle for 150°.

    View hint and full working

    Hint: 150° is in Quadrant 2, so subtract it from 180°.

    Working
    180° − 150° = 30°
    Answer: 30°
  8. Find the reference angle for 225°.

    View hint and full working

    Hint: 225° is in Quadrant 3, so subtract 180°.

    Working
    225° − 180° = 45°
    Answer: 45°
  9. Find the reference angle for 330°.

    View hint and full working

    Hint: 330° is in Quadrant 4, so subtract it from 360°.

    Working
    360° − 330° = 30°
    Answer: 30°
  10. A ship travels on a bearing of 300°. Is this direction closer to north-west or north-east?

    View hint and full working

    Hint: A bearing of 300° lies between west and north.

    Working
    Bearings are measured clockwise from north.
    270° is west and 360° (or 0°) is north.
    Therefore, 300° is in the north-west direction.
    Answer: north-west
NSW Year 9–10 Maths Guide
Trigonometry Made Simple for NSW Students

Trigonometry helps students connect angles and side lengths in triangles. In NSW high school maths, students usually begin with right-angled triangles and SOH CAH TOA, then move into the Sine Rule, Cosine Rule, area rule and the four quadrants using the CAST rule.

Quick syllabus note: This guide is written as a practical NESA-aligned Year 9–10 support page. Schools may sequence topics slightly differently depending on their program, pathway and class level.

Trigonometry Topics Covered in This Article

This article explains the main trigonometry topics students commonly study across Year 9 and Year 10 in NSW.

  • Year 9: Right-Angled Triangles and SOH CAH TOA
  • Year 9: The Law of Sines, also called the Sine Rule
  • Year 10: The Cosine Rule
  • Year 10: Area of a Triangle Using Trigonometry
  • Year 10: The Four Quadrants and the CAST Rule

1. Right-Angled Triangles and SOH CAH TOA (Year 9)

In Year 9 trigonometry, students usually begin with right-angled triangles. The main goal is to find a missing side or missing angle by choosing the correct trigonometric ratio.

A right-angled triangle has one angle of \(90^\circ\). The longest side is called the hypotenuse. The other two sides are labelled opposite and adjacent, depending on the angle being used.

SOH: \( \sin\theta = \frac{\text{Opposite}}{\text{Hypotenuse}} \)

CAH: \( \cos\theta = \frac{\text{Adjacent}}{\text{Hypotenuse}} \)

TOA: \( \tan\theta = \frac{\text{Opposite}}{\text{Adjacent}} \)

Known sides Ratio to use Memory clue
Opposite and Hypotenuse Sine SOH
Adjacent and Hypotenuse Cosine CAH
Opposite and Adjacent Tangent TOA
Important: The opposite and adjacent sides change depending on which angle is being used. Always mark the angle first before choosing sine, cosine or tangent.
Worked Example

Find the missing side

A right-angled triangle has an angle of \(30^\circ\) and a hypotenuse of 10 cm. Find the side opposite the angle.

  1. Opposite and hypotenuse are involved, so use sine.
  2. \( \sin 30^\circ = \frac{\text{Opposite}}{10} \)
  3. \( 0.5 = \frac{\text{Opposite}}{10} \)
  4. \( \text{Opposite} = 5 \)
Answer: The opposite side is 5 cm.
Worked Example

Find the missing angle

In a right-angled triangle, the opposite side is 6 m and the adjacent side is 8 m. Find the angle \( \theta \).

  1. Opposite and adjacent are involved, so use tangent.
  2. \( \tan\theta = \frac{6}{8} \)
  3. \( \theta = \tan^{-1}(0.75) \)
  4. \( \theta \approx 36.9^\circ \)
Answer: \( \theta \approx 36.9^\circ \)
Trigonometry formula image showing the Law of Sines, Cosine Rule and area of a triangle formula for NSW Year 9 and Year 10 maths students
Law of Sines, Cosine Rule and area of a triangle formula for NSW trigonometry students.

2. The Law of Sines (Sine Rule) (Year 9)

The Law of Sines, commonly called the Sine Rule, is used when a triangle does not have a right angle. SOH CAH TOA works directly for right-angled triangles, but the Sine Rule helps students solve some non-right-angled triangles.

Sine Rule: \( \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} \)

Capital letters \(A\), \(B\), and \(C\) represent angles. Lowercase letters \(a\), \(b\), and \(c\) represent the sides opposite those angles.

When to use the Sine Rule
  • When two angles and one side are known.
  • When two sides and a non-included angle are known.
  • When a side can be matched with its opposite angle.
Student tip

The most important step is matching each side with its opposite angle. Side \(a\) is opposite angle \(A\), side \(b\) is opposite angle \(B\), and side \(c\) is opposite angle \(C\).

Worked Example

Find a missing side using the Sine Rule

In triangle \(ABC\), \(A = 40^\circ\), \(B = 60^\circ\), and side \(a = 10\) cm. Find side \(b\).

  1. Match the side with its opposite angle: \(a \leftrightarrow A\), \(b \leftrightarrow B\).
  2. \( \frac{a}{\sin A} = \frac{b}{\sin B} \)
  3. \( \frac{10}{\sin 40^\circ} = \frac{b}{\sin 60^\circ} \)
  4. \( b = \frac{10\sin 60^\circ}{\sin 40^\circ} \)
  5. \( b \approx 13.47 \) cm
Answer: \( b \approx 13.47 \) cm.

3. The Cosine Rule (Year 10)

The Cosine Rule is used for non-right-angled triangles when the Sine Rule is not suitable. It is especially useful when students know two sides and the included angle, or when all three sides are known.

Cosine Rule: \( c^2 = a^2 + b^2 - 2ab\cos C \)

Use it for SAS

If two sides and the angle between them are known, the Cosine Rule can be used to find the missing side.

Use it for SSS

If all three sides are known, the Cosine Rule can be rearranged to find a missing angle.

Worked Example

Find a missing side using the Cosine Rule

A triangle has sides \(a = 7\) cm and \(b = 9\) cm with an included angle \(C = 60^\circ\). Find side \(c\).

  1. \( c^2 = a^2 + b^2 - 2ab\cos C \)
  2. \( c^2 = 7^2 + 9^2 - 2(7)(9)\cos 60^\circ \)
  3. \( c^2 = 49 + 81 - 126(0.5) \)
  4. \( c^2 = 67 \)
  5. \( c = \sqrt{67} \approx 8.19 \)
Answer: \( c \approx 8.19 \) cm.

4. Area of a Triangle Using Trigonometry (Year 10)

Students can also use trigonometry to find the area of a triangle when the perpendicular height is not given. This is useful when two sides and the included angle are known.

Area Rule: \( \text{Area} = \frac{1}{2}ab\sin C \)

In this formula, \(a\) and \(b\) are two known sides, and \(C\) is the angle between them. If the included angle is not given directly, students may need to find it first using another trigonometry rule.

Worked Example

Find the area using two sides and an included angle

A triangle has sides \(a = 8\) cm and \(b = 12\) cm with an included angle \(C = 45^\circ\). Find the area.

  1. \( \text{Area} = \frac{1}{2}ab\sin C \)
  2. \( \text{Area} = \frac{1}{2}(8)(12)\sin 45^\circ \)
  3. \( \text{Area} = 48 \times 0.7071 \)
  4. \( \text{Area} \approx 33.94 \)
Answer: The area is approximately \(33.94\text{ cm}^2\).

5. The Four Quadrants (CAST) (Year 10)

In Year 10 trigonometry, students may extend their understanding beyond acute angles and begin working with angles across the full \(360^\circ\) plane. The CAST Rule helps students remember which trigonometric ratios are positive in each quadrant.

Quadrant Angle range Positive ratio CAST letter
Quadrant 1 \(0^\circ\) to \(90^\circ\) All ratios are positive A
Quadrant 2 \(90^\circ\) to \(180^\circ\) Sine is positive S
Quadrant 3 \(180^\circ\) to \(270^\circ\) Tangent is positive T
Quadrant 4 \(270^\circ\) to \(360^\circ\) Cosine is positive C
Memory trick: CAST is often remembered as “All Students Take Calculators”. Starting from Quadrant 1 and moving anticlockwise, the positive ratios are All, Sine, Tangent and Cosine.

This topic is important for questions involving quadrants, bearings, direction and angles greater than \(90^\circ\). For bearings, students should remember that directions are usually measured clockwise from north.

Common mistake: Students often forget whether sine, cosine or tangent is positive or negative in a quadrant. Draw the quadrant diagram first before solving.

How to Study Trigonometry Effectively

The best way to improve in trigonometry is to practise one skill at a time. Students should first master SOH CAH TOA, then move to the Sine Rule, Cosine Rule, area rule and finally quadrant-based questions.

  1. Revise opposite, adjacent and hypotenuse.
  2. Practise choosing between sine, cosine and tangent.
  3. Use inverse trigonometry when finding angles.
  4. Learn when to use the Sine Rule and Cosine Rule.
  5. Practise area rule questions using two sides and an included angle.
  6. Use the CAST rule for quadrant questions.

For extra practice, visit our free maths worksheets, practice tests, and Year 10 Maths NSW syllabus guide.

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Navigating Trigonometry in the NSW NESA Syllabus

Understanding the exact expectations of the NESA mathematics syllabus can sometimes be overwhelming. In NSW, trigonometry is introduced and expanded upon during Stage 5, which spans Year 9 and Year 10. However, the exact topics a student will face depend heavily on their year level and their specific mathematical pathway.

Year 9 vs. Year 10: What is the Difference?

Generally, Year 9 students focus on building a rock-solid foundation. The curriculum introduces basic trigonometric ratios strictly within right-angled triangles. Students spend their time mastering SOH CAH TOA, finding missing sides and angles, and applying these skills to simple word problems. While some schools may introduce the Sine Rule early, Year 9 students typically do not need to know advanced formulas like the Cosine Rule unless they are in an accelerated class.

In Year 10, the training wheels come off. The syllabus extends into complex, non-right-angled triangles and advanced problem-solving. Students must master the Sine Rule, the Cosine Rule, the area of a triangle using trigonometry, navigational bearings, and the CAST Rule for analyzing angles across the full 360-degree plane.

Stage 5.2 vs. Stage 5.3 Mathematics Pathways

In NSW schools, Stage 5 math is split into different pathways that dictate the difficulty of the trigonometry taught:

  • Stage 5.2 Trigonometry: This pathway is highly practical. It focuses on using trigonometric ratios to solve standard, real-world problems, primarily sticking to right-angled triangles.

  • Stage 5.3 Trigonometry: This is the advanced pathway, crucial for students planning to take higher-level mathematics in Years 11 and 12. Stage 5.3 students tackle non-right-angled geometry, exact values, 3D trigonometry, and quadrant-based calculations.

Mastering the Core Trigonometric Rules

To succeed in high school exams, students must know exactly when and how to apply specific trigonometric rules.

SOH CAH TOA

SOH CAH TOA is the ultimate memory trick for solving right-angled triangles. It tells students exactly which ratio to use based on the information provided in the question

The golden rule of SOH CAH TOA is that it only works directly in right-angled triangles. If the question gives you the hypotenuse and asks for the opposite side, you use Sine. If it gives you the opposite and adjacent sides and asks for an angle, you use the inverse Tangent.

Moving Beyond 90 Degrees: The CAST Rule

In Year 10, trigonometry no longer stops at 90°. Students must calculate angles across a full 360° Cartesian plane. This is where the CAST Rule becomes essential. It dictates which trigonometric ratios are positive in each of the four quadrants:

Understanding CAST prevents major exam mistakes. For example, many students panic when their calculator gives them a negative cosine value and assume their working out is wrong. However, a negative cosine is perfectly normal! While cos60° is positive (Quadrant 1), cos120° is negative because 120° falls into Quadrant 2, where only Sine is positive.

The Biggest Hurdle: Navigational Bearings

Ask any high school student in NSW what the hardest part of trigonometry is, and they will likely say bearings.

Many students struggle with bearings because they confuse them with standard trigonometric angles. A standard angle is measured anti-clockwise from the horizontal x-axis. A bearing, however, is always measured clockwise from True North. This single difference causes massive confusion when students attempt to draw their diagrams.

Furthermore, bearing questions are essentially “boss fights” that test multiple skills at once. To solve a single bearings question, a student might need to combine:

  • Navigational direction (North, South, East, West)

  • Alternate and co-interior angles (parallel line rules)

  • Right-angled triangle analysis (SOH CAH TOA)

  • The Sine Rule or Cosine Rule

Our top tutoring tip: Never try to solve a bearings question in your head. Always draw a large, clear diagram first. Mark True North, sketch the bearing angle, and isolate the specific triangle you need to solve the problem.

Frequently Asked Questions about Trigonometry

In NSW, trigonometry is usually taught across Stage 5, which commonly covers Year 9 and Year 10. The exact order can vary depending on the school, class level and whether the student is studying a Core, Standard, 5.2 or 5.3 pathway.

Generally, Year 9 students begin with the basic trigonometric ratios in right-angled triangles. This includes SOH CAH TOA, finding missing sides, finding missing angles, and applying trigonometry to simple word problems. Many students are also introduced to the Sine Rule for non-right-angled triangles.

In Year 10, students usually extend their knowledge to more advanced trigonometry topics such as the Cosine Rule, area of a triangle using trigonometry, bearings, and the CAST Rule for angles in the four quadrants.

The safest way to understand the NSW approach is that trigonometry develops from basic right-angled triangles into non-right-angled triangles, bearings and quadrant-based problems.

It depends on the school and the class pathway. In many NSW schools, the Cosine Rule is taught more commonly in Year 10, especially when students are working with non-right-angled triangles.

However, some advanced Year 9 classes may introduce the Cosine Rule earlier, especially if the students are studying at a higher level or preparing for accelerated maths pathways.

For most Year 9 students, the main focus should be on:

  • SOH CAH TOA
  • right-angled triangle problems
  • finding missing sides and angles
  • basic applications of trigonometry
  • the Sine Rule, if taught by the school

So, generally, Year 9 students do not need to master the Cosine Rule unless their school has specifically included it in their program.

In NSW, Stage 5 maths is usually studied across Year 9 and Year 10. Stage 5.2 and Stage 5.3 refer to different levels of depth and difficulty.

Stage 5.2 trigonometry usually focuses on using trigonometric ratios to solve practical problems, especially with right-angled triangles and standard applications.

Stage 5.3 trigonometry is more advanced. Students may work with more complex non-right-angled triangles, the Sine Rule, Cosine Rule, area rule, bearings, exact values, and quadrant-based trigonometry. Stage 5.3 is often important for students who want to continue into higher-level mathematics in Years 11 and 12.

A simple way to understand it is this: Stage 5.2 builds strong trigonometry skills, while Stage 5.3 extends those skills into more advanced problem-solving and preparation for senior maths.

SOH CAH TOA is a memory trick used for trigonometry in right-angled triangles.

Students should use SOH CAH TOA when the triangle has a right angle and they need to find a missing side or a missing angle.

For example, if the question gives an angle and the hypotenuse, and asks for the opposite side, students should use sine. If the question gives the opposite and adjacent sides and asks for an angle, students should use tangent and inverse tan.

The most important rule is: SOH CAH TOA only works directly in right-angled triangles.

The CAST Rule is important because trigonometry does not stop at angles between 0° and 90° In Year 10 and higher-level maths, students often work with angles across the full 360° plane.

The CAST Rule helps students remember which trigonometric ratios are positive in each quadrant:

  • Quadrant 1: All are positive
  • Quadrant 2: Sine is positive
  • Quadrant 3: Tangent is positive
  • Quadrant 4: Cosine is positive

This matters because values such as sin, cos and tan are based on acute reference angles, but the final answer may be positive or negative depending on the quadrant.

For example, cos 60° is positive, but cos 120° is negative because 120° is in Quadrant 2, where cosine is negative.

Knowing the CAST Rule helps students understand signs, reference angles and exact trigonometric values without relying only on a calculator.

Many students struggle with bearings because they confuse bearings with normal trigonometric angles.

  • A standard trigonometric angle is usually measured anticlockwise from the positive x-axis.
  • A bearing, however, is measured clockwise from north.

This difference can confuse students when they are trying to draw diagrams or decide which angle belongs inside the triangle.

Students also struggle because bearing questions often combine several skills at once, including:

  • direction
  • angle facts
  • parallel lines
  • right-angled triangles
  • SOH CAH TOA
  • Sine Rule or Cosine Rule
  • worded problem interpretation

 

The best way to solve bearings questions is to draw a clear diagram first, mark north carefully, write the bearing angle, and then identify the triangle needed to solve the problem.

No. A negative cosine value does not mean the answer is wrong.

Cosine is positive in Quadrant 1 and Quadrant 4, but it is negative in Quadrant 2 and Quadrant 3.

For example:

cos 60° is positive because 60° is in Quadrant 1.

cos 120° is negative because 120°  is in Quadrant 2.

So if a cosine value is negative, students should not automatically assume they made a mistake. They should check which quadrant the angle is in and apply the CAST Rule.

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