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Geometry Formulae for 2D Shapes: Area Formulas & Practice

All Squares, Rectangles, Rhombuses are Parallelograms. Hence,
Area of a Parallelogram, Rhombus, Rectangle & Square = Base × Perpendicular height

Area of a Rhombus, Square and Kite = ½ × d₁ × d₂


A triangle can be thought of as half of a parallelogram. Therefore: Area of a Triangle = ½ × Base × Perpendicular Height

For a trapezium, we take the average of the two parallel sides and multiply it by the perpendicular height: Area of a Trapezium = ½ × (a + b) × h

Area of a Circle = πr²
Geometry formulae poster showing and circles, triangles and quadrilaterals formulae

Table of Contents

Infographic showing area formulas for parallelograms, rectangles, squares, rhombuses, kites, trapeziums and triangles, explaining how many formulas relate to base × perpendicular height or diagonals.
Interactive geometry practice

2D Shape Area Formulae Practice Questions

Practise the main area formulae without memorising them as unrelated rules. Start with base × perpendicular height, then see how the same idea connects to triangles, trapeziums, diagonals and circles.

Start with the core idea Area = Base × Perpendicular Height Then simplify the pattern: triangle = half; trapezium = average parallel sides × height; square and rhombus can also use diagonals; kite uses diagonals; circle uses πr².
  • Base × height: parallelogram, rectangle, square and rhombus
  • Diagonal formulae: square, rhombus and kite
  • Derived area formulae: triangle and trapezium
  • Circle area: radius, diameter and A = πr²
  • 8 shape topics
  • 56 practice questions
  • 7 questions per topic
  • Hints and full working
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Topic 1 Parallelogram Area 7 questions · Base × perpendicular height 0/7

b h

A parallelogram uses the core area idea directly: multiply the base by the perpendicular height. A = b × h

Tip: Enter the numerical answer only. The question already tells you the unit.
  1. A parallelogram has a base of 8 cm and a perpendicular height of 5 cm. Find its area.

    View hint and full working

    Hint: Use A = b × h.

    Working
    A = 8 × 5
    A = 40 cm²
    Answer: 40 cm²
  2. A parallelogram has a base of 12 m and a perpendicular height of 7 m. Find its area.

    View hint and full working

    Hint: Multiply the base by the perpendicular height.

    Working
    A = 12 × 7
    A = 84 m²
    Answer: 84 m²
  3. The area of a parallelogram is 54 cm² and its base is 9 cm. Find the perpendicular height.

    View hint and full working

    Hint: Rearrange A = b × h to h = A ÷ b.

    Working
    h = 54 ÷ 9
    h = 6 cm
    Answer: 6 cm
  4. The area of a parallelogram is 96 m² and its perpendicular height is 8 m. Find the base.

    View hint and full working

    Hint: Rearrange A = b × h to b = A ÷ h.

    Working
    b = 96 ÷ 8
    b = 12 m
    Answer: 12 m
  5. A parallelogram has a base of 15 cm and a perpendicular height of 4.5 cm. Find its area.

    View hint and full working

    Hint: Use A = b × h.

    Working
    A = 15 × 4.5
    A = 67.5 cm²
    Answer: 67.5 cm²
  6. A parallelogram has a base of 11 cm, a perpendicular height of 6 cm and a sloping side of 8 cm. Find its area.

    View hint and full working

    Hint: The sloping side is not needed for area. Use the perpendicular height.

    Working
    A = 11 × 6
    A = 66 cm²
    Answer: 66 cm²
  7. A parallelogram has area 105 cm² and base 15 cm. Find its perpendicular height.

    View hint and full working

    Hint: Height = area ÷ base.

    Working
    h = 105 ÷ 15
    h = 7 cm
    Answer: 7 cm

Topic 2 Rectangle Area 7 questions · Length × width 0/7

l w

A rectangle is a special parallelogram. Its length and width are already perpendicular, so area is length × width. A = l × w

Tip: Enter the numerical answer only. The question already tells you the unit.
  1. A rectangle is 9 cm long and 4 cm wide. Find its area.

    View hint and full working

    Hint: Use A = l × w.

    Working
    A = 9 × 4
    A = 36 cm²
    Answer: 36 cm²
  2. A rectangle is 12 m long and 7 m wide. Find its area.

    View hint and full working

    Hint: Multiply length by width.

    Working
    A = 12 × 7
    A = 84 m²
    Answer: 84 m²
  3. A rectangle has an area of 72 cm² and a length of 9 cm. Find its width.

    View hint and full working

    Hint: Width = area ÷ length.

    Working
    w = 72 ÷ 9
    w = 8 cm
    Answer: 8 cm
  4. A rectangle has an area of 150 m² and a width of 10 m. Find its length.

    View hint and full working

    Hint: Length = area ÷ width.

    Working
    l = 150 ÷ 10
    l = 15 m
    Answer: 15 m
  5. A rectangle is 6.5 cm long and 4 cm wide. Find its area.

    View hint and full working

    Hint: Use A = l × w.

    Working
    A = 6.5 × 4
    A = 26 cm²
    Answer: 26 cm²
  6. A rectangular garden is 14 m long and 3.5 m wide. Find its area.

    View hint and full working

    Hint: Multiply the two perpendicular side lengths.

    Working
    A = 14 × 3.5
    A = 49 m²
    Answer: 49 m²
  7. A rectangle has area 96 cm² and width 6 cm. Find its length.

    View hint and full working

    Hint: Length = area ÷ width.

    Working
    l = 96 ÷ 6
    l = 16 cm
    Answer: 16 cm

Topic 3 Square Area — Two Useful Formulae 7 questions · Side² and diagonals 0/7

s d₁ d₂

A square can be treated as a rectangle, so A = s². Its diagonals are also perpendicular and equal, so A = ½d₁d₂ works too. A = s² or A = ½d₁d₂

Tip: Enter the numerical answer only. The question already tells you the unit.
  1. A square has side length 6 cm. Find its area.

    View hint and full working

    Hint: Use A = s².

    Working
    A = 6²
    A = 36 cm²
    Answer: 36 cm²
  2. A square has side length 9 m. Find its area.

    View hint and full working

    Hint: Square the side length.

    Working
    A = 9²
    A = 81 m²
    Answer: 81 m²
  3. A square has area 64 cm². Find its side length.

    View hint and full working

    Hint: The side is the square root of the area.

    Working
    s = √64
    s = 8 cm
    Answer: 8 cm
  4. A square has diagonals of length 8 cm each. Find its area using A = ½d₁d₂.

    View hint and full working

    Hint: Both diagonals are 8 cm.

    Working
    A = ½ × 8 × 8
    A = 32 cm²
    Answer: 32 cm²
  5. A square has diagonals of length 10 m each. Find its area using the diagonal formula.

    View hint and full working

    Hint: Use A = ½d₁d₂.

    Working
    A = ½ × 10 × 10
    A = 50 m²
    Answer: 50 m²
  6. A square has side length 5 cm. Find its area.

    View hint and full working

    Hint: Use A = s².

    Working
    A = 5²
    A = 25 cm²
    Answer: 25 cm²
  7. A square has diagonals of length 14 cm each. Find its area.

    View hint and full working

    Hint: Use A = ½d₁d₂.

    Working
    A = ½ × 14 × 14
    A = 98 cm²
    Answer: 98 cm²

Topic 4 Rhombus Area — Two Useful Formulae 7 questions · Base-height and diagonals 0/7

d₁ d₂

A rhombus is a parallelogram, so it uses base × perpendicular height. Because its diagonals are perpendicular, it can also use ½d₁d₂. A = b × h or A = ½d₁d₂

Tip: Enter the numerical answer only. The question already tells you the unit.
  1. A rhombus has a base of 10 cm and perpendicular height of 6 cm. Find its area.

    View hint and full working

    Hint: Use A = b × h.

    Working
    A = 10 × 6
    A = 60 cm²
    Answer: 60 cm²
  2. A rhombus has a base of 8.5 m and perpendicular height of 4 m. Find its area.

    View hint and full working

    Hint: Use base × perpendicular height.

    Working
    A = 8.5 × 4
    A = 34 m²
    Answer: 34 m²
  3. A rhombus has area 72 cm² and base 9 cm. Find the perpendicular height.

    View hint and full working

    Hint: Height = area ÷ base.

    Working
    h = 72 ÷ 9
    h = 8 cm
    Answer: 8 cm
  4. A rhombus has diagonals 12 cm and 8 cm. Find its area.

    View hint and full working

    Hint: Use A = ½d₁d₂.

    Working
    A = ½ × 12 × 8
    A = 48 cm²
    Answer: 48 cm²
  5. A rhombus has diagonals 14 m and 10 m. Find its area.

    View hint and full working

    Hint: Use the diagonal formula.

    Working
    A = ½ × 14 × 10
    A = 70 m²
    Answer: 70 m²
  6. A rhombus has area 54 cm² and one diagonal is 12 cm. Find the other diagonal.

    View hint and full working

    Hint: Use 54 = ½ × 12 × d₂.

    Working
    54 = 6d₂
    d₂ = 9 cm
    Answer: 9 cm
  7. A rhombus has area 112 cm² and base 16 cm. Find its perpendicular height.

    View hint and full working

    Hint: Use h = A ÷ b.

    Working
    h = 112 ÷ 16
    h = 7 cm
    Answer: 7 cm

Topic 5 Kite Area 7 questions · Perpendicular diagonals 0/7

d₁ d₂

A kite can be split into triangles by its perpendicular diagonals. That gives the compact area formula ½ × d₁ × d₂. A = ½d₁d₂

Tip: Enter the numerical answer only. The question already tells you the unit.
  1. A kite has diagonals 10 cm and 6 cm. Find its area.

    View hint and full working

    Hint: Use A = ½d₁d₂.

    Working
    A = ½ × 10 × 6
    A = 30 cm²
    Answer: 30 cm²
  2. A kite has diagonals 14 m and 8 m. Find its area.

    View hint and full working

    Hint: Multiply the diagonals, then halve.

    Working
    A = ½ × 14 × 8
    A = 56 m²
    Answer: 56 m²
  3. A kite has diagonals 9 cm and 12 cm. Find its area.

    View hint and full working

    Hint: Use the diagonal area formula.

    Working
    A = ½ × 9 × 12
    A = 54 cm²
    Answer: 54 cm²
  4. A kite has area 40 cm² and one diagonal is 10 cm. Find the other diagonal.

    View hint and full working

    Hint: Use 40 = ½ × 10 × d₂.

    Working
    40 = 5d₂
    d₂ = 8 cm
    Answer: 8 cm
  5. A kite has area 63 m² and one diagonal is 14 m. Find the other diagonal.

    View hint and full working

    Hint: Rearrange A = ½d₁d₂.

    Working
    63 = 7d₂
    d₂ = 9 m
    Answer: 9 m
  6. A kite has diagonals 15 cm and 4.8 cm. Find its area.

    View hint and full working

    Hint: Use A = ½d₁d₂.

    Working
    A = ½ × 15 × 4.8
    A = 36 cm²
    Answer: 36 cm²
  7. A kite has area 84 cm² and one diagonal is 12 cm. Find the other diagonal.

    View hint and full working

    Hint: Use 84 = ½ × 12 × d₂.

    Working
    84 = 6d₂
    d₂ = 14 cm
    Answer: 14 cm

Topic 6 Triangle Area 7 questions · Half of base × height 0/7

b h

A triangle is half of a parallelogram with the same base and perpendicular height. That is why its area is ½bh. A = ½b × h

Tip: Enter the numerical answer only. The question already tells you the unit.
  1. A triangle has base 8 cm and perpendicular height 5 cm. Find its area.

    View hint and full working

    Hint: Use A = ½bh.

    Working
    A = ½ × 8 × 5
    A = 20 cm²
    Answer: 20 cm²
  2. A triangle has base 12 m and perpendicular height 9 m. Find its area.

    View hint and full working

    Hint: Multiply base and height, then halve.

    Working
    A = ½ × 12 × 9
    A = 54 m²
    Answer: 54 m²
  3. A triangle has area 35 cm² and base 10 cm. Find its perpendicular height.

    View hint and full working

    Hint: Use h = 2A ÷ b.

    Working
    h = (2 × 35) ÷ 10
    h = 7 cm
    Answer: 7 cm
  4. A triangle has area 48 m² and perpendicular height 8 m. Find its base.

    View hint and full working

    Hint: Use b = 2A ÷ h.

    Working
    b = (2 × 48) ÷ 8
    b = 12 m
    Answer: 12 m
  5. A triangle has base 7.5 cm and perpendicular height 4 cm. Find its area.

    View hint and full working

    Hint: Use A = ½bh.

    Working
    A = ½ × 7.5 × 4
    A = 15 cm²
    Answer: 15 cm²
  6. A triangle has base 18 cm and perpendicular height 6 cm. Find its area.

    View hint and full working

    Hint: Use half of base × height.

    Working
    A = ½ × 18 × 6
    A = 54 cm²
    Answer: 54 cm²
  7. A parallelogram with the same base and height as a triangle has area 80 cm². What is the triangle's area?

    View hint and full working

    Hint: A triangle is half of the matching parallelogram.

    Working
    Triangle area = 80 ÷ 2
    A = 40 cm²
    Answer: 40 cm²

Topic 7 Trapezium Area 7 questions · Average parallel sides × height 0/7

a b h

For a trapezium, first average the two parallel sides, then multiply by the perpendicular height. A = ½(a + b)h

Tip: Enter the numerical answer only. The question already tells you the unit.
  1. A trapezium has parallel sides 8 cm and 12 cm, with perpendicular height 5 cm. Find its area.

    View hint and full working

    Hint: Use A = ½(a + b)h.

    Working
    A = ½ × (8 + 12) × 5
    A = ½ × 20 × 5
    A = 50 cm²
    Answer: 50 cm²
  2. A trapezium has parallel sides 6 m and 10 m, with height 4 m. Find its area.

    View hint and full working

    Hint: Average the parallel sides, then multiply by height.

    Working
    A = ½ × (6 + 10) × 4
    A = 32 m²
    Answer: 32 m²
  3. A trapezium has parallel sides 9 cm and 15 cm, with height 6 cm. Find its area.

    View hint and full working

    Hint: Use A = ½(a + b)h.

    Working
    A = ½ × 24 × 6
    A = 72 cm²
    Answer: 72 cm²
  4. A trapezium has area 45 cm², parallel sides 6 cm and 12 cm. Find its height.

    View hint and full working

    Hint: Use 45 = ½(6 + 12)h.

    Working
    45 = 9h
    h = 5 cm
    Answer: 5 cm
  5. A trapezium has area 84 m², one parallel side 8 m and height 7 m. Find the other parallel side.

    View hint and full working

    Hint: Use 84 = ½(8 + b) × 7.

    Working
    84 = 3.5(8 + b)
    24 = 8 + b
    b = 16 m
    Answer: 16 m
  6. A trapezium has parallel sides 5.5 cm and 10.5 cm, with height 4 cm. Find its area.

    View hint and full working

    Hint: Add the parallel sides, halve, then multiply by height.

    Working
    A = ½ × 16 × 4
    A = 32 cm²
    Answer: 32 cm²
  7. A trapezium has parallel sides 14 cm and 20 cm, with height 3 cm. Find its area.

    View hint and full working

    Hint: Use A = ½(a + b)h.

    Working
    A = ½ × 34 × 3
    A = 51 cm²
    Answer: 51 cm²

Topic 8 Circle Area 7 questions · Radius and π 0/7

r

For circle questions, find the radius first. Then square the radius and multiply by π. Use π = 3.14 for these questions. A = πr²

Tip: Enter the numerical answer only. The question already tells you the unit.
  1. Use π = 3.14. A circle has radius 4 cm. Find its area.

    View hint and full working

    Hint: Use A = πr².

    Working
    A = 3.14 × 4²
    A = 3.14 × 16
    A = 50.24 cm²
    Answer: 50.24 cm²
  2. Use π = 3.14. A circle has radius 7 m. Find its area.

    View hint and full working

    Hint: Square the radius before multiplying by π.

    Working
    A = 3.14 × 7²
    A = 3.14 × 49
    A = 153.86 m²
    Answer: 153.86 m²
  3. Use π = 3.14. A circle has diameter 10 cm. Find its area.

    View hint and full working

    Hint: First divide the diameter by 2 to get the radius.

    Working
    r = 10 ÷ 2 = 5
    A = 3.14 × 5²
    A = 78.5 cm²
    Answer: 78.5 cm²
  4. Use π = 3.14. A circle has diameter 12 m. Find its area.

    View hint and full working

    Hint: Radius is half the diameter.

    Working
    r = 12 ÷ 2 = 6
    A = 3.14 × 6²
    A = 113.04 m²
    Answer: 113.04 m²
  5. Use π = 3.14. A circle has area 314 cm². Find its radius.

    View hint and full working

    Hint: Rearrange to r² = A ÷ π.

    Working
    r² = 314 ÷ 3.14
    r² = 100
    r = 10 cm
    Answer: 10 cm
  6. Use π = 3.14. A circle has radius 3 cm. Find its area.

    View hint and full working

    Hint: Use A = πr².

    Working
    A = 3.14 × 3²
    A = 3.14 × 9
    A = 28.26 cm²
    Answer: 28.26 cm²
  7. Use π = 3.14. A circle has area 200.96 cm². Find its radius.

    View hint and full working

    Hint: First find r² by dividing the area by π.

    Working
    r² = 200.96 ÷ 3.14
    r² = 64
    r = 8 cm
    Answer: 8 cm

Geometry Formulae for 2D Shapes

Geometry becomes much easier when you stop treating every area formula as a completely separate rule. Most common 2D area formulae come from a few simple relationships involving base, perpendicular height and diagonals. This guide covers circles, triangles, rectangles, squares, parallelograms, rhombuses, kites and trapeziums.

The main idea: many area formulae can be understood from Area = Base × Perpendicular Height Rectangles, squares, parallelograms and rhombuses use this idea directly. A triangle uses half of it. A trapezium uses the average of its parallel sides as the base. Kite and rhombus diagonal formulae can be understood by dividing the shapes into triangles.

Area Formulae for Common 2D Shapes

Shape Area Formula Simple Idea
Parallelogram A = b × h Base × perpendicular height
Rectangle A = l × w Length and width act as base and height
Square A = s² Base and height are both equal to the side
Rhombus A = b × h A rhombus is a special parallelogram
Rhombus using diagonals A = ½d₁d₂ Can be divided into right triangles
Kite A = ½d₁d₂ Uses its perpendicular diagonals
Triangle A = ½bh Half of a parallelogram with the same base and height
Trapezium A = ½(a + b)h Average of the parallel sides × height
Circle A = πr² Can be understood by rearranging circle sectors
Easy way to remember: do not memorise every area formula as an unrelated rule. Start with base × perpendicular height and then ask: is the shape using the whole area, half of it, an average base, or diagonals?

Circle Formulae and Key Terms

A circle is a 2D shape where every point on its boundary is the same distance from the centre.

Radius
r
Diameter
d = 2r
Circumference
C = 2πr = πd
Area
A = πr²
Arc length
(θ ÷ 360°) × 2πr
Sector area
(θ ÷ 360°) × πr²

Chord: a line segment joining two points on the circumference. The diameter is the longest chord. Arc: part of the circumference. Sector: the region between two radii and their connecting arc.

Student tip: if a question gives the diameter, divide it by 2 before using a formula that requires the radius.

Triangle Formulae and Rules

A triangle can be viewed as half of a parallelogram with the same base and perpendicular height. Therefore: A = ½ × base × perpendicular height
Area of a triangle
A = ½bh
Angle sum
A + B + C = 180°
Pythagoras' theorem
a² + b² = c²
Equilateral triangle area
A = (√3 ÷ 4)s²
Heron's formula
A = √[s(s-a)(s-b)(s-c)]

For Heron's formula: s = (a + b + c) ÷ 2. Pythagoras' theorem applies only to right-angled triangles, where c is the hypotenuse.

Types of Triangles

  • Equilateral: three equal sides and three 60° angles.
  • Isosceles: at least two equal sides.
  • Scalene: all three side lengths are different.
  • Right-angled: one angle is 90°.
  • Acute: all angles are less than 90°.
  • Obtuse: one angle is greater than 90°.

Quadrilateral Formulae

Key rule: the interior angles of every quadrilateral add up to 360°.

Parallelogram, Rectangle, Square and Rhombus

Squares, rectangles and rhombuses are special types of parallelograms. This is why their area can be connected to the same basic idea: base × perpendicular height.

Parallelogram area
A = bh
Parallelogram perimeter
P = 2(a + b)
Rectangle area
A = length × width
Rectangle perimeter
P = 2(l + w)
Rectangle diagonal
d = √(l² + w²)
Square area
A = s²
Square perimeter
P = 4s
Square diagonal
d = s√2
Rhombus area
A = bh
Rhombus area using diagonals
A = ½d₁d₂
Rhombus perimeter
P = 4a

Kite Formulae

Using the inclusive definition, a kite is a quadrilateral with two pairs of adjacent equal sides. Rhombuses and squares therefore satisfy the kite condition as special cases.

Kite area
A = ½d₁d₂
Kite perimeter
P = 2(a + b)

Trapezium Formula

A trapezium has a pair of parallel sides. Instead of using one base, take the average of the two parallel sides and multiply by the perpendicular height.

A = ½(a + b)h where a and b are the parallel sides and h is the perpendicular height.

Parallel Line and Angle Rules

When a transversal crosses two parallel lines:
Corresponding angles
Equal
Alternate interior angles
Equal
Alternate exterior angles
Equal
Vertically opposite angles
Equal
Student tip: mark equal angles on the diagram before doing any calculations. It often makes the solution much easier to see.

Frequently Asked Questions about Geometry Formulae

In NSW, it depends entirely on your school’s assessment policy for Years 7 to 10. Some schools allow students to bring a custom, handwritten reference sheet with formulas and examples. Others provide a generic, standardized formula sheet, while some do not allow any reference sheets at all. Always check with your maths teacher before your exam.

NAPLAN Years 7 and 9 numeracy can include measurement and geometry questions involving shapes, length, area, spatial reasoning and related concepts. The exact mix of question types varies between tests.

Stage 4 (Years 7 & 8) focuses heavily on the properties of 2D and 3D shapes, teaching students how to calculate basic area and perimeter, and identifying the vertices, edges, and faces of prisms and pyramids. Stage 5 (Years 9 & 10) is highly application-based, introducing challenging topics like trigonometry, true bearings, and applying Pythagoras’ theorem within 3D shapes.

These geometry skills can support the mathematical reasoning required in OC and Selective tests. However, the placement tests assess reasoning rather than requiring students to memorise a fixed list of geometry formulae. Students should use the official NSW Department of Education practice tests to understand the question style.

The easiest way is to understand the relationship between shapes instead of blindly memorising each formula separately.

For example:

  • For a parallelogram: Area = base × height
  • Because squares, rectangles, and rhombuses are technically parallelograms, the area of all these shapes is base × height
  • A triangle is half of a parallelogram, so its area is: ½ ×
  • base × height
  • A trapezium is like two parallel sides averaged together, so its area is: Area = ½ × (a + b) × height
  • A prism is a 3D shape with the same cross-section all the way through, so its volume is: Volume of a prism = cross-sectional area × length
  • For circles, remember that the
    1. Diameter = 2 × radius
    2. Circumference = 2πr
    3. Area = πr²

A good exam tip is to group formulae by shape, draw a quick diagram, label the known values, and always check the units. Area uses square units such as cm², while volume uses cubic units such as cm³.

The secret to solving Year 9 and 10 circle geometry is mastering the core formulas first. Once you confidently know the Area (πr²) and Circumference (2πr) of a full circle, finding the area of a sector or the length of an arc is easy—you simply multiply your full circle formula by the fraction of the angle given (Angle ÷ 360°).

NSW curriculum is stage-based, and Stage 4 encompasses Years 7–8. The official syllabus structure includes Pythagoras and trigonometry in the Stage 4/5 Core, but schools have flexibility in sequencing learning within stages.

It comes down to reading the context clues carefully. If the word problem mentions “fencing,” “border,” “outside,” or “walking around,” you need to calculate the perimeter. If the question mentions “covering,” “painting,” “flooring,” or finding the “inside space,” you need to calculate the area.

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Think of them as the “superpower” of numbers — once you understand them, a whole world of advanced math becomes much easier to conquer!

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