Probability: Complete Guide, Examples & Practice Questions

Learn probability from primary chance concepts to advanced Stage 5 topics with clear explanations, worked examples and 102 free interactive practice questions for NSW students.
Chance and Probability for Year NSW Students

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Interactive maths practice

Probability Practice Test

Build probability skills from primary-school chance language through sample spaces, theoretical and experimental probability, multistage events, Venn diagrams, dependent events and Stage 5 further probability.

  • 12 topic-based levels
  • 102 practice questions
  • Instant answer checks
  • Hints and full working
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Level 1 Primary Chance Language & Probability Scale 10 questions · Primary foundation 0/10

Tip: Use chance words carefully: impossible, unlikely, even chance, likely and certain.
  1. A number is chosen from {2, 4, 6, 8}. How likely is it that the number is even?

    View hint and full working

    Hint: Every number in the set is even.

    Working
    Possible outcomes: 2, 4, 6, 8.
    All 4 outcomes are even.
    So the event must happen.
    Answer: Certain
  2. A standard six-sided die is rolled. How likely is it to roll a 7?

    View hint and full working

    Hint: Check whether 7 is in the sample space {1, 2, 3, 4, 5, 6}.

    Working
    A standard die can only show 1, 2, 3, 4, 5 or 6.
    Rolling a 7 cannot happen.
    Answer: Impossible
  3. A bag contains 9 red counters and 1 blue counter. One counter is chosen at random. How likely is red?

    View hint and full working

    Hint: Red has many more favourable outcomes than blue, but it is not certain.

    Working
    There are 10 counters altogether.
    9 of the 10 counters are red.
    Red is very likely, but not certain.
    Answer: Likely
  4. A bag contains 1 green counter and 9 yellow counters. One counter is chosen at random. How likely is green?

    View hint and full working

    Hint: Green can happen, but there is only 1 green counter out of 10.

    Working
    There are 10 counters altogether.
    Only 1 counter is green.
    Green is possible but unlikely.
    Answer: Unlikely
  5. A fair coin is tossed once. How likely is heads?

    View hint and full working

    Hint: A fair coin has two equally likely outcomes.

    Working
    The outcomes are H and T.
    Heads has probability 1/2.
    A probability of 1/2 is an even chance.
    Answer: Even chance
  6. A spinner has 4 equal sections: 2 red and 2 blue. How likely is landing on red?

    View hint and full working

    Hint: Compare the number of red sections with the total number of equal sections.

    Working
    2 of the 4 equal sections are red.
    P(red) = 2/4 = 1/2.
    So red has an even chance.
    Answer: Even chance
  7. A bag contains 5 blue counters and no red counters. How likely is choosing red?

    View hint and full working

    Hint: There are no red counters in the bag.

    Working
    Number of red counters = 0.
    The event cannot happen.
    Therefore it is impossible.
    Answer: Impossible
  8. A card is chosen from cards labelled 1, 2, 3 and 4. How likely is the card number to be less than 5?

    View hint and full working

    Hint: Check every possible card.

    Working
    All possible cards are 1, 2, 3 or 4.
    Every one of them is less than 5.
    Therefore the event is certain.
    Answer: Certain
  9. A standard die is rolled. How likely is the result to be less than 6?

    View hint and full working

    Hint: Five of the six outcomes are less than 6.

    Working
    Favourable outcomes: 1, 2, 3, 4, 5.
    That is 5 outcomes out of 6.
    The event is likely, but not certain.
    Answer: Likely
  10. A standard die is rolled. How likely is it to roll exactly 6?

    View hint and full working

    Hint: Only one of the six equally likely outcomes is a 6.

    Working
    There is 1 favourable outcome out of 6.
    The probability is 1/6.
    That makes rolling a 6 unlikely.
    Answer: Unlikely

Level 2 Outcomes, Events & Sample Spaces 10 questions · Core foundations 0/10

Tip: List or count every possible outcome systematically before calculating probability.
  1. How many outcomes are in the sample space for one fair coin toss?

    View hint and full working

    Hint: The possible outcomes are heads and tails.

    Working
    Sample space = {H, T}.
    Number of outcomes = 2.
    Answer: 2
  2. How many ordered outcomes are possible when two fair coins are tossed?

    View hint and full working

    Hint: List HH, HT, TH and TT.

    Working
    Sample space = {HH, HT, TH, TT}.
    Number of outcomes = 4.
    Answer: 4
  3. How many outcomes are in the sample space for one standard six-sided die?

    View hint and full working

    Hint: The die can show the numbers 1 through 6.

    Working
    Sample space = {1, 2, 3, 4, 5, 6}.
    Number of outcomes = 6.
    Answer: 6
  4. For one standard die, how many outcomes are in the event “roll an even number”?

    View hint and full working

    Hint: Identify the even values in {1, 2, 3, 4, 5, 6}.

    Working
    Even outcomes = {2, 4, 6}.
    Number of favourable outcomes = 3.
    Answer: 3
  5. How many ordered outcomes are possible when two standard dice are rolled?

    View hint and full working

    Hint: Each first-die result can be paired with 6 second-die results.

    Working
    First die: 6 possibilities.
    Second die: 6 possibilities.
    Total ordered outcomes = 6 × 6 = 36.
    Answer: 36
  6. A spinner has 5 equal sections labelled A, B, C, D and E. How many outcomes are in its sample space?

    View hint and full working

    Hint: Each label is one possible outcome.

    Working
    Sample space = {A, B, C, D, E}.
    Number of outcomes = 5.
    Answer: 5
  7. Two fair coins are tossed. How many outcomes contain at least one head?

    View hint and full working

    Hint: List all four outcomes and exclude only the outcome with no heads.

    Working
    Sample space = {HH, HT, TH, TT}.
    At least one head: HH, HT, TH.
    Number of favourable outcomes = 3.
    Answer: 3
  8. A standard die is rolled. How many outcomes are greater than 4?

    View hint and full working

    Hint: Look for values 5 and 6.

    Working
    Outcomes greater than 4 are {5, 6}.
    Number of favourable outcomes = 2.
    Answer: 2
  9. A fair coin is tossed and a standard die is rolled. How many ordered outcomes are possible?

    View hint and full working

    Hint: Multiply the number of coin outcomes by the number of die outcomes.

    Working
    Coin outcomes = 2.
    Die outcomes = 6.
    Total outcomes = 2 × 6 = 12.
    Answer: 12
  10. Three fair coins are tossed. How many ordered outcomes are possible?

    View hint and full working

    Hint: Each toss has 2 possible outcomes.

    Working
    Number of outcomes = 2 × 2 × 2.
    2³ = 8.
    There are 8 ordered outcomes.
    Answer: 8

Level 3 Simple Theoretical Probability & Conversions 10 questions · Fractions, decimals & percentages 0/10

Tip: For equally likely outcomes, probability = favourable outcomes ÷ total outcomes.
  1. A fair die is rolled. Find P(even).

    View hint and full working

    Hint: There are 3 even outcomes out of 6 equally likely outcomes.

    Working
    Even outcomes = {2, 4, 6}.
    P(even) = 3/6 = 1/2.
    Answer: 1/2 (0.5)
  2. A fair die is rolled. Find P(prime number).

    View hint and full working

    Hint: The prime numbers on a die are 2, 3 and 5.

    Working
    Prime outcomes = {2, 3, 5}.
    P(prime) = 3/6 = 1/2.
    Answer: 1/2 (0.5)
  3. One card is drawn from a standard 52-card deck. Find P(ace).

    View hint and full working

    Hint: There are 4 aces in 52 cards.

    Working
    P(ace) = 4/52.
    Simplify by dividing by 4.
    P(ace) = 1/13.
    Answer: 1/13
  4. One card is drawn from a standard deck. Find P(heart).

    View hint and full working

    Hint: There are 13 hearts in a 52-card deck.

    Working
    P(heart) = 13/52.
    13/52 = 1/4.
    Answer: 1/4 (0.25)
  5. A spinner has 8 equal sections and 3 are blue. Find P(blue).

    View hint and full working

    Hint: Use blue sections ÷ total equal sections.

    Working
    Favourable outcomes = 3.
    Total outcomes = 8.
    P(blue) = 3/8 = 0.375.
    Answer: 3/8 (0.375)
  6. A bag contains 4 red and 6 blue counters. One counter is chosen at random. Find P(red).

    View hint and full working

    Hint: There are 4 red counters out of 10 total.

    Working
    P(red) = 4/10.
    Simplify: 4/10 = 2/5 = 0.4.
    Answer: 2/5 (0.4)
  7. Write the probability 0.25 as a percentage.

    View hint and full working

    Hint: Multiply the decimal by 100.

    Working
    0.25 × 100 = 25.
    Therefore 0.25 = 25%.
    Answer: 25%
  8. Write 60% as a probability in decimal form.

    View hint and full working

    Hint: Divide the percentage by 100.

    Working
    60% = 60/100.
    60/100 = 0.6.
    Answer: 0.6
  9. Write 3/5 as a decimal probability.

    View hint and full working

    Hint: Divide 3 by 5.

    Working
    3 ÷ 5 = 0.6.
    So 3/5 = 0.6.
    Answer: 0.6
  10. A fair die is rolled. Find P(not rolling 1).

    View hint and full working

    Hint: Five outcomes are not 1.

    Working
    Not 1 = {2, 3, 4, 5, 6}.
    P(not 1) = 5/6.
    Answer: 5/6

Level 4 Complementary Events 8 questions · P(not A) = 1 − P(A) 0/8

Tip: An event and its complement always have probabilities that add to 1.
  1. If P(rain) = 0.30, find P(no rain).

    View hint and full working

    Hint: Subtract the given probability from 1.

    Working
    P(no rain) = 1 − 0.30.
    = 0.70.
    Answer: 0.70
  2. If P(win) = 0.65, find P(not win).

    View hint and full working

    Hint: Use P(not A) = 1 − P(A).

    Working
    P(not win) = 1 − 0.65.
    = 0.35.
    Answer: 0.35
  3. If P(not A) = 0.18, find P(A).

    View hint and full working

    Hint: The two probabilities must add to 1.

    Working
    P(A) = 1 − 0.18.
    = 0.82.
    Answer: 0.82
  4. A fair die is rolled. Find P(not rolling a 6).

    View hint and full working

    Hint: The complement of rolling a 6 is any of the other five outcomes.

    Working
    P(6) = 1/6.
    P(not 6) = 1 − 1/6 = 5/6.
    Answer: 5/6
  5. Two fair coins are tossed. Find P(at least one head).

    View hint and full working

    Hint: Use the complement: “no heads” means TT.

    Working
    P(no heads) = P(TT) = 1/4.
    P(at least one head) = 1 − 1/4.
    = 3/4.
    Answer: 3/4 (0.75)
  6. If P(missing the bus) = 0.12, find P(not missing the bus).

    View hint and full working

    Hint: Subtract from 1.

    Working
    P(not missing) = 1 − 0.12.
    = 0.88.
    Answer: 0.88
  7. If P(A) = 3/8, find P(not A).

    View hint and full working

    Hint: Write 1 as 8/8 and subtract.

    Working
    P(not A) = 1 − 3/8.
    = 8/8 − 3/8 = 5/8.
    Answer: 5/8 (0.625)
  8. If P(no homework tonight) = 0.40, find P(homework tonight).

    View hint and full working

    Hint: Homework and no homework are complementary events in this model.

    Working
    P(homework) = 1 − 0.40.
    = 0.60.
    Answer: 0.60

Level 5 Experimental Probability & Relative Frequency 8 questions · Trials, simulations & expected frequency 0/8

Tip: Experimental probability uses observed frequency ÷ number of trials.
  1. A coin is tossed 60 times and lands heads 34 times. Find the experimental probability of heads as a simplified fraction.

    View hint and full working

    Hint: Use frequency ÷ number of trials, then simplify.

    Working
    Experimental P(heads) = 34/60.
    Divide numerator and denominator by 2.
    = 17/30.
    Answer: 17/30
  2. A die is rolled 120 times and a 6 appears 18 times. Find the experimental probability of rolling a 6 as a simplified fraction.

    View hint and full working

    Hint: Use 18 ÷ 120 and simplify.

    Working
    Experimental P(6) = 18/120.
    Divide by 6: 18/120 = 3/20.
    = 0.15.
    Answer: 3/20 (0.15)
  3. A spinner is spun 50 times and lands red 15 times. Find the experimental probability of red.

    View hint and full working

    Hint: Divide the red frequency by the total spins.

    Working
    Experimental P(red) = 15/50.
    = 3/10 = 0.30.
    Answer: 0.30
  4. An event occurs 42 times in 70 trials. Find its experimental probability.

    View hint and full working

    Hint: Calculate 42 ÷ 70.

    Working
    42/70 simplifies to 3/5.
    3/5 = 0.60.
    Answer: 0.60
  5. A simulation is run 80 times and an event occurs 24 times. Find its relative frequency.

    View hint and full working

    Hint: Relative frequency is the observed frequency divided by the number of trials.

    Working
    Relative frequency = 24/80.
    = 3/10 = 0.30.
    Answer: 0.30
  6. A simulation is run 250 times and an event occurs 95 times. Find its relative frequency.

    View hint and full working

    Hint: Divide the observed frequency by the total number of trials.

    Working
    Relative frequency = 95/250.
    Simplify: 95/250 = 19/50.
    = 0.38.
    Answer: 0.38
  7. An experiment has relative frequency 0.42 after 100 trials. How many times did the event occur?

    View hint and full working

    Hint: Observed frequency = relative frequency × number of trials.

    Working
    Observed frequency = 0.42 × 100.
    = 42.
    Answer: 42
  8. A fair coin has theoretical P(heads) = 0.50. An experiment gives P(heads) = 0.48. What is the absolute difference between the two probabilities?

    View hint and full working

    Hint: Subtract the smaller probability from the larger one.

    Working
    Difference = 0.50 − 0.48.
    = 0.02.
    Answer: 0.02

Level 6 Organising Sample Spaces & Two-Stage Outcomes 8 questions · Coins, dice & systematic counting 0/8

Tip: For multistage experiments, organise outcomes with a list, table or counting rule.
  1. Two fair dice are rolled. Find P(sum = 7).

    View hint and full working

    Hint: Count the ordered pairs that total 7.

    Working
    Successful pairs: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1).
    6 successful outcomes out of 36.
    P(sum 7) = 6/36 = 1/6.
    Answer: 1/6
  2. Two fair dice are rolled. Find P(a double).

    View hint and full working

    Hint: A double has the same number on both dice.

    Working
    Doubles: (1,1), (2,2), (3,3), (4,4), (5,5), (6,6).
    6 out of 36 outcomes.
    P(double) = 1/6.
    Answer: 1/6
  3. Two fair dice are rolled. Find P(sum = 10).

    View hint and full working

    Hint: List the ordered pairs that add to 10.

    Working
    Successful pairs: (4,6), (5,5), (6,4).
    3 out of 36 outcomes.
    P(sum 10) = 3/36 = 1/12.
    Answer: 1/12
  4. Two fair coins are tossed. Find P(exactly one head).

    View hint and full working

    Hint: The favourable outcomes are HT and TH.

    Working
    Sample space = {HH, HT, TH, TT}.
    Exactly one head: HT, TH.
    P = 2/4 = 1/2.
    Answer: 1/2
  5. Three fair coins are tossed. Find P(all heads).

    View hint and full working

    Hint: Only HHH gives all heads.

    Working
    There are 2³ = 8 equally likely outcomes.
    Only HHH is favourable.
    P(all heads) = 1/8.
    Answer: 1/8
  6. A fair coin is tossed and a standard die is rolled. Find P(heads and an even number).

    View hint and full working

    Hint: There are 12 equally likely combined outcomes or multiply independent probabilities.

    Working
    P(heads) = 1/2.
    P(even) = 3/6 = 1/2.
    P(heads and even) = 1/2 × 1/2 = 1/4.
    Answer: 1/4
  7. A spinner has 4 equally likely outcomes and a fair coin is tossed. How many combined ordered outcomes are possible?

    View hint and full working

    Hint: Multiply the number of spinner outcomes by the number of coin outcomes.

    Working
    Spinner outcomes = 4.
    Coin outcomes = 2.
    Total = 4 × 2 = 8.
    Answer: 8
  8. Three fair coins are tossed. Find P(exactly two heads).

    View hint and full working

    Hint: List HHT, HTH and THH.

    Working
    Exactly two heads occurs in HHT, HTH and THH.
    3 favourable outcomes out of 8.
    P = 3/8.
    Answer: 3/8

Level 7 Independent Events 8 questions · Multiplication rule 0/8

Tip: For independent events, one result does not change the probability of the other.
  1. Two fair coins are tossed. Find P(heads on both coins).

    View hint and full working

    Hint: The coin tosses are independent.

    Working
    P(H on first) = 1/2.
    P(H on second) = 1/2.
    P(H and H) = 1/2 × 1/2 = 1/4.
    Answer: 1/4
  2. A fair die is rolled twice. Find P(rolling a 6 both times).

    View hint and full working

    Hint: The two die rolls are independent.

    Working
    P(6) = 1/6 on each roll.
    P(6 then 6) = 1/6 × 1/6.
    = 1/36.
    Answer: 1/36
  3. Independent events A and B have P(A) = 0.4 and P(B) = 0.5. Find P(A and B).

    View hint and full working

    Hint: Multiply the probabilities because the events are independent.

    Working
    P(A and B) = 0.4 × 0.5.
    = 0.20.
    Answer: 0.20
  4. A fair coin is tossed three times. Find P(HHH).

    View hint and full working

    Hint: Multiply 1/2 three times.

    Working
    P(HHH) = 1/2 × 1/2 × 1/2.
    = 1/8.
    Answer: 1/8
  5. A spinner lands red with probability 0.3. It is spun twice independently. Find P(red both times).

    View hint and full working

    Hint: Multiply 0.3 by 0.3.

    Working
    P(red both) = 0.3 × 0.3.
    = 0.09.
    Answer: 0.09
  6. A fair die is rolled and a fair coin is tossed. Find P(even number and tails).

    View hint and full working

    Hint: The die and coin results are independent.

    Working
    P(even) = 3/6 = 1/2.
    P(tails) = 1/2.
    P(even and tails) = 1/2 × 1/2 = 1/4.
    Answer: 1/4
  7. Independent events A and B have P(A) = 2/3 and P(B) = 3/5. Find P(A and B).

    View hint and full working

    Hint: Multiply and simplify.

    Working
    P(A and B) = 2/3 × 3/5.
    = 6/15 = 2/5.
    Answer: 2/5
  8. Independent events A and B have P(A and B) = 0.24 and P(A) = 0.6. Find P(B).

    View hint and full working

    Hint: For independent events, P(A and B) = P(A)P(B).

    Working
    0.24 = 0.6 × P(B).
    P(B) = 0.24 ÷ 0.6.
    = 0.40.
    Answer: 0.40

Level 8 Dependent Events & Without Replacement 8 questions · Changing probabilities 0/8

Tip: Without replacement, update both the number of favourable outcomes and the total before the next draw.
  1. A bag has 3 red and 2 blue counters. Two counters are drawn without replacement. Find P(red then red).

    View hint and full working

    Hint: After one red is removed, 2 red remain out of 4 counters.

    Working
    P(first red) = 3/5.
    P(second red | first red) = 2/4.
    P(red then red) = 3/5 × 2/4 = 6/20 = 3/10.
    Answer: 3/10
  2. A bag has 4 green and 6 yellow counters. Two are drawn without replacement. Find P(green then green).

    View hint and full working

    Hint: After drawing one green, 3 green remain out of 9 counters.

    Working
    P(first green) = 4/10.
    P(second green | first green) = 3/9.
    P = 4/10 × 3/9 = 12/90 = 2/15.
    Answer: 2/15
  3. Two cards are drawn from a standard deck without replacement. Find P(ace then ace).

    View hint and full working

    Hint: After one ace is drawn, 3 aces remain among 51 cards.

    Working
    P(first ace) = 4/52.
    P(second ace | first ace) = 3/51.
    P = 4/52 × 3/51 = 12/2652 = 1/221.
    Answer: 1/221
  4. A bag has 5 red and 3 blue counters. Two are drawn without replacement. Find P(red then blue).

    View hint and full working

    Hint: After a red is removed, 3 blue remain out of 7 counters.

    Working
    P(first red) = 5/8.
    P(second blue | first red) = 3/7.
    P = 5/8 × 3/7 = 15/56.
    Answer: 15/56
  5. There are 10 tickets, 2 of which are winners. Two tickets are chosen without replacement. Find P(both are winners).

    View hint and full working

    Hint: After selecting one winning ticket, only 1 winner remains among 9 tickets.

    Working
    P(first winner) = 2/10.
    P(second winner | first winner) = 1/9.
    P = 2/10 × 1/9 = 2/90 = 1/45.
    Answer: 1/45
  6. Two cards are drawn from a standard deck without replacement. Find P(heart then heart).

    View hint and full working

    Hint: After one heart is drawn, 12 hearts remain among 51 cards.

    Working
    P(first heart) = 13/52 = 1/4.
    P(second heart | first heart) = 12/51 = 4/17.
    P = 1/4 × 4/17 = 1/17.
    Answer: 1/17
  7. A bag has 2 white and 3 black counters. Two are drawn without replacement. Find P(white then black).

    View hint and full working

    Hint: After a white counter is drawn, all 3 black counters remain among 4 counters.

    Working
    P(first white) = 2/5.
    P(second black | first white) = 3/4.
    P = 2/5 × 3/4 = 6/20 = 3/10.
    Answer: 3/10
  8. A bag has 6 red and 4 blue counters. The first counter drawn is known to be red and is not replaced. Find P(the second counter is red).

    View hint and full working

    Hint: Condition on the first draw already being red.

    Working
    After one red is removed, 5 red counters remain.
    There are 9 counters remaining in total.
    P(second red | first red) = 5/9.
    Answer: 5/9

Level 9 Multistage Events & Tree-Diagram Thinking 8 questions · Multiple pathways 0/8

Tip: Multiply along a pathway; add separate successful pathways when more than one route gives the required event.
  1. Two fair coins are tossed. Find P(exactly one head).

    View hint and full working

    Hint: The successful pathways are HT and TH.

    Working
    P(HT) = 1/2 × 1/2 = 1/4.
    P(TH) = 1/4.
    Add the pathways: 1/4 + 1/4 = 1/2.
    Answer: 1/2
  2. Three fair coins are tossed. Find P(exactly two heads).

    View hint and full working

    Hint: There are three successful pathways: HHT, HTH and THH.

    Working
    Each specific pathway has probability 1/8.
    There are 3 successful pathways.
    P(exactly two heads) = 3 × 1/8 = 3/8.
    Answer: 3/8
  3. Three fair coins are tossed. Find P(at least one head).

    View hint and full working

    Hint: Use the complement of getting no heads.

    Working
    P(no heads) = P(TTT) = 1/8.
    P(at least one head) = 1 − 1/8.
    = 7/8.
    Answer: 7/8
  4. A fair die is rolled and then a fair coin is tossed. Find P(odd number and heads).

    View hint and full working

    Hint: Multiply the probability of an odd die result by the probability of heads.

    Working
    P(odd) = 3/6 = 1/2.
    P(heads) = 1/2.
    P(odd and heads) = 1/2 × 1/2 = 1/4.
    Answer: 1/4
  5. A spinner has P(red) = 0.4 and P(blue) = 0.6. It is spun twice independently. Find P(one red and one blue in any order).

    View hint and full working

    Hint: Add the RB and BR pathways.

    Working
    P(RB) = 0.4 × 0.6 = 0.24.
    P(BR) = 0.6 × 0.4 = 0.24.
    Total = 0.24 + 0.24 = 0.48.
    Answer: 0.48
  6. Independent events A and B have P(A) = 0.7 and P(B) = 0.2. Find P(A occurs and B does not occur).

    View hint and full working

    Hint: Use P(not B) = 1 − 0.2 before multiplying.

    Working
    P(not B) = 0.8.
    P(A and not B) = 0.7 × 0.8.
    = 0.56.
    Answer: 0.56
  7. A process succeeds with probability 0.8 on each of 3 independent attempts. Find P(all 3 attempts succeed).

    View hint and full working

    Hint: Multiply 0.8 three times.

    Working
    P(all succeed) = 0.8³.
    = 0.512.
    Answer: 0.512
  8. An item is defective with probability 0.05. Two items are selected independently. Find P(at least one is defective).

    View hint and full working

    Hint: Use the complement: both items are not defective.

    Working
    P(not defective) = 0.95.
    P(neither defective) = 0.95² = 0.9025.
    P(at least one defective) = 1 − 0.9025 = 0.0975.
    Answer: 0.0975

Level 10 Mutually Exclusive Events, OR & Overlap 8 questions · Addition rule 0/8

Tip: If events overlap, subtract the intersection once so it is not counted twice.
  1. A fair die is rolled. Find P(rolling 1 or 2).

    View hint and full working

    Hint: The events are mutually exclusive on one die roll.

    Working
    Favourable outcomes = {1, 2}.
    P = 2/6 = 1/3.
    Answer: 1/3
  2. One card is drawn from a standard deck. Find P(king or queen).

    View hint and full working

    Hint: A single card cannot be both a king and a queen.

    Working
    There are 4 kings and 4 queens.
    Favourable cards = 8.
    P = 8/52 = 2/13.
    Answer: 2/13
  3. A fair die is rolled. Find P(even or a multiple of 3).

    View hint and full working

    Hint: The overlap is the outcome 6.

    Working
    Even = {2, 4, 6}.
    Multiples of 3 = {3, 6}.
    Union = {2, 3, 4, 6}.
    P = 4/6 = 2/3.
    Answer: 2/3
  4. One card is drawn from a standard deck. Find P(heart or king).

    View hint and full working

    Hint: The king of hearts belongs to both events, so subtract it once.

    Working
    P(heart or king) = (13 + 4 − 1)/52.
    = 16/52.
    = 4/13.
    Answer: 4/13
  5. Mutually exclusive events A and B have P(A) = 0.35 and P(B) = 0.25. Find P(A or B).

    View hint and full working

    Hint: For mutually exclusive events, simply add the probabilities.

    Working
    P(A or B) = 0.35 + 0.25.
    = 0.60.
    Answer: 0.60
  6. Events A and B have P(A) = 0.6, P(B) = 0.5 and P(A and B) = 0.2. Find P(A or B).

    View hint and full working

    Hint: Use P(A or B) = P(A) + P(B) − P(A and B).

    Working
    P(A or B) = 0.6 + 0.5 − 0.2.
    = 0.9.
    Answer: 0.90
  7. A fair die is rolled. Find P(result less than 3 or greater than 4).

    View hint and full working

    Hint: List the favourable values.

    Working
    Less than 3: {1, 2}.
    Greater than 4: {5, 6}.
    4 favourable outcomes out of 6.
    P = 4/6 = 2/3.
    Answer: 2/3
  8. A whole number from 1 to 10 is chosen at random. Find P(multiple of 2 or multiple of 5).

    View hint and full working

    Hint: Count the overlap at 10 only once.

    Working
    Multiples of 2: {2, 4, 6, 8, 10}.
    Multiples of 5: {5, 10}.
    Union = {2, 4, 5, 6, 8, 10}.
    P = 6/10 = 3/5.
    Answer: 3/5

Level 11 Venn Diagrams & Two-Way Tables 8 questions · Sets, counts & probability from data 0/8

Tip: Fill intersections first, then “only” regions, totals and finally probabilities.
  1. In a class of 30 students, 18 play soccer, 12 play basketball and 5 play both. How many play at least one of the two sports?

    View hint and full working

    Hint: Use n(S ∪ B) = n(S) + n(B) − n(S ∩ B).

    Working
    At least one = 18 + 12 − 5.
    = 25.
    Answer: 25
  2. Using the same class: 30 students, 18 soccer, 12 basketball and 5 both. How many play neither sport?

    View hint and full working

    Hint: Subtract the number who play at least one sport from the class total.

    Working
    At least one = 18 + 12 − 5 = 25.
    Neither = 30 − 25.
    = 5.
    Answer: 5
  3. In a group of 40 students, 22 study music, 18 study art and 10 study both. How many study music only?

    View hint and full working

    Hint: Remove the students in the overlap from the music total.

    Working
    Music only = 22 − 10.
    = 12.
    Answer: 12
  4. In a group of 50 students, 28 travel by bus, 20 walk and 8 do both at different times. How many are in the union of bus or walk?

    View hint and full working

    Hint: Add the group totals and subtract the overlap once.

    Working
    Bus or walk = 28 + 20 − 8.
    = 40.
    Answer: 40
  5. A survey of 80 students shows: 48 play sport and 32 do not. Of the 48 who play sport, 30 are boys. Of the 32 who do not play sport, 14 are boys. Find P(a randomly chosen student is a boy).

    View hint and full working

    Hint: First find the total number of boys.

    Working
    Total boys = 30 + 14 = 44.
    P(boy) = 44/80.
    = 11/20 = 0.55.
    Answer: 11/20 (0.55)
  6. Using the same survey of 80 students, where 48 play sport, find P(play sport).

    View hint and full working

    Hint: Use the sport total over the survey total.

    Working
    P(play sport) = 48/80.
    Simplify: 48/80 = 3/5 = 0.60.
    Answer: 3/5 (0.60)
  7. Using the same survey, 30 of the 80 students are boys who play sport. Find P(boy and plays sport).

    View hint and full working

    Hint: Use the intersection count over the total number surveyed.

    Working
    P(boy and sport) = 30/80.
    Simplify: 30/80 = 3/8.
    = 0.375.
    Answer: 3/8 (0.375)
  8. In the survey, there are 44 boys in total and 30 of them play sport. Find P(plays sport | boy).

    View hint and full working

    Hint: Once we know the student is a boy, the relevant sample space is the 44 boys.

    Working
    Boys who play sport = 30.
    Total boys = 44.
    P(sport | boy) = 30/44 = 15/22.
    Answer: 15/22

Level 12 Conditional & Further Probability 8 questions · Stage 5 extension 0/8

Tip: Conditional probability changes the sample space to cases where the given condition is already true.
  1. A card is known to be a face card (J, Q or K) from a standard deck. Find P(the card is a king | it is a face card).

    View hint and full working

    Hint: There are 12 face cards, including 4 kings.

    Working
    Face cards = 4 jacks + 4 queens + 4 kings = 12.
    Kings among face cards = 4.
    Conditional probability = 4/12 = 1/3.
    Answer: 1/3
  2. A fair die result is known to be even. Find P(result > 3 | result is even).

    View hint and full working

    Hint: Restrict the sample space to the even outcomes.

    Working
    Given even, the sample space is {2, 4, 6}.
    Values greater than 3 are {4, 6}.
    P = 2/3.
    Answer: 2/3
  3. A card is known to be a heart. Find P(the card is an ace | it is a heart).

    View hint and full working

    Hint: There are 13 hearts and only one is the ace of hearts.

    Working
    Conditional sample space = 13 hearts.
    Favourable card = ace of hearts.
    P = 1/13.
    Answer: 1/13
  4. In a group of 60 students, 36 play sport. Of those 36, 18 take the bus. Find P(bus | plays sport).

    View hint and full working

    Hint: The condition restricts the sample space to the 36 students who play sport.

    Working
    Bus and sport = 18.
    Sport total = 36.
    P(bus | sport) = 18/36 = 1/2.
    Answer: 1/2
  5. Events A and B have P(A and B) = 0.18 and P(B) = 0.30. Find P(A | B).

    View hint and full working

    Hint: Use P(A | B) = P(A and B) ÷ P(B).

    Working
    P(A | B) = 0.18 ÷ 0.30.
    = 0.60.
    Answer: 0.60
  6. If P(A | B) = 0.40 and P(B) = 0.50, find P(A and B).

    View hint and full working

    Hint: Rearrange P(A | B) = P(A and B) ÷ P(B).

    Working
    P(A and B) = P(A | B) × P(B).
    = 0.40 × 0.50.
    = 0.20.
    Answer: 0.20
  7. Events A and B are independent and P(A) = 0.70. Find P(A | B).

    View hint and full working

    Hint: For independent events, knowing B occurred does not change P(A).

    Working
    Because A and B are independent:
    P(A | B) = P(A).
    = 0.70.
    Answer: 0.70
  8. In a group of 40 students, 22 like apples, 16 like bananas and 8 like both. Find P(likes apples | likes bananas).

    View hint and full working

    Hint: Use the banana group as the conditional sample space.

    Working
    Students who like both = 8.
    Students who like bananas = 16.
    P(apples | bananas) = 8/16 = 1/2.
    Answer: 1/2

Probability in NSW Mathematics: What Students Need to Know

Probability is the mathematics of chance and uncertainty. Students learn how to describe possible outcomes, calculate how likely events are, compare theoretical results with experiments, and solve increasingly complex problems involving more than one event.

In the current NSW Mathematics K–10 syllabus, probability forms part of the Statistics and probability area. For Years 7–10, probability develops from fundamental ideas such as outcomes and sample spaces into multistage probability. Some Stage 5 pathways extend this further through more advanced probability concepts.

Important for NSW students

Schools do not necessarily teach every probability idea in exactly the same school year. Focus on understanding the concepts your class is currently studying rather than assuming that a topic belongs only to Year 7, Year 8, Year 9 or Year 10.

1. Probability Basics: Chance, Outcomes, Events and Sample Spaces

A random experiment is an activity where the exact result cannot be known in advance. Rolling a die, tossing a coin or drawing a card are common examples.

  • Outcome: one possible result of an experiment.
  • Sample space: the complete set of possible outcomes.
  • Event: one outcome or a group of outcomes we are interested in.
  • Equally likely outcomes: outcomes that have the same chance of occurring.
Example: Rolling a standard six-sided die

Sample space = {1, 2, 3, 4, 5, 6}

If event E is “roll an even number”, then: E = {2, 4, 6}.

The Probability Scale

Probability is measured from 0 to 1 inclusive. It can also be written as a fraction, decimal or percentage.

Probability Meaning Example
0 Impossible Rolling a 7 on a standard six-sided die
Close to 0 Unlikely Choosing one particular card from a full deck
0.5 Even chance Getting heads on a fair coin
Close to 1 Likely Rolling a number less than 6 on a fair die
1 Certain Rolling a number from 1 to 6 on a standard die

2. Calculating Theoretical Probability

When all outcomes are equally likely, probability can be calculated using:

P(E) = Number of favourable outcomes ÷ Total number of possible outcomes
Common mistake: This formula assumes the outcomes are equally likely. Do not automatically use “favourable ÷ total” if different outcomes have different probabilities.
Example: Rolling an even number

A fair die has 6 equally likely outcomes.

Even outcomes = {2, 4, 6}, so there are 3 favourable outcomes.

P(even) = 3/6 = 1/2 = 0.5 = 50%

Probability with Playing Cards

A standard deck contains 52 cards: 4 suits, 13 cards in each suit and 4 cards of each rank.

Example: Drawing an ace
P(ace) = 4/52 = 1/13

3. Complementary Events

A complementary event describes an event not happening. The probability of an event and its complement must add to 1.

P(A) + P(not A) = 1

Therefore:

P(not A) = 1 − P(A)
Example

If P(rain) = 0.35:

P(no rain) = 1 − 0.35 = 0.65
Useful shortcut

Sometimes finding the probability of an event directly is difficult. It can be much easier to calculate the probability of the opposite event and subtract it from 1.

4. Experimental Probability and Relative Frequency

Theoretical probability tells us what we expect to happen. Experimental probability uses results collected from an actual experiment or simulation.

Experimental probability = Number of times the event occurs ÷ Number of trials
Example

A coin is tossed 100 times and lands on heads 46 times.

Experimental P(heads) = 46/100 = 0.46

The theoretical probability is 0.5. An experimental result does not have to match the theoretical probability exactly.

What Happens When the Number of Trials Increases?

With a fair random process, experimental results will often become more stable as the number of trials increases. This is why simulations with many trials can be useful when studying probability.

5. Organising Sample Spaces

For simple experiments, a list may be enough. For multistage experiments, students need systematic ways to make sure no outcomes are missed.

Two Coins

Possible outcomes:

{HH, HT, TH, TT}

There are 4 equally likely outcomes, so:

P(two heads) = 1/4

Two Dice

Two dice create 36 ordered outcomes. An outcome table is usually more reliable than trying to list all 36 outcomes mentally.

Example: Probability that both dice are even

Each die has 3 even numbers out of 6.

P(both even) = 3/6 × 3/6 = 1/4

6. Independent and Dependent Events

Independent Events

Events are independent when the result of one event does not change the probability of the other.

For independent events:

P(A and B) = P(A) × P(B)
Example: Tossing two fair coins
P(H and H) = 1/2 × 1/2 = 1/4

Dependent Events

Events are dependent when the first event changes the probability of the next event.

This commonly happens when an item is selected and not replaced.

Example: Two red counters without replacement

A bag contains 3 red and 2 blue counters.

Probability the first counter is red = 3/5. After taking one red counter out, 2 red counters remain among 4 counters.

P(red then red) = 3/5 × 2/4 = 6/20 = 3/10
Watch out: Do not automatically multiply the original probability twice when sampling without replacement. The probability can change after the first selection.

7. Multistage Probability and Tree Diagrams

A multistage event involves two or more stages. Examples include tossing several coins, rolling more than one die, or selecting several objects one after another.

Tree diagrams are useful because they display the possible pathways through an experiment.

  1. Draw a branch for each possible result of the first event.
  2. Add branches for the possible results of the next event.
  3. Write the relevant probability on each branch.
  4. Multiply probabilities along a pathway when all events on that pathway must occur.
  5. Add separate successful pathways when more than one pathway produces the required result.
Example: Exactly one head from two fair coin tosses

The successful pathways are HT and TH.

Each pathway has probability:

1/2 × 1/2 = 1/4

There are two successful pathways:

P(exactly one head) = 1/4 + 1/4 = 1/2

8. Mutually Exclusive Events and the Addition Rule

Two events are mutually exclusive if they cannot happen at the same time in one trial.

Example

When rolling one die, “roll a 2” and “roll a 5” are mutually exclusive. You cannot roll both with the same die at the same time.

For mutually exclusive events:

P(A or B) = P(A) + P(B)
Example: Drawing a king or queen
P(king or queen) = 4/52 + 4/52 = 8/52 = 2/13

When Events Can Overlap

If events A and B can both occur, their overlap must not be counted twice.

P(A or B) = P(A) + P(B) − P(A and B)
Example: Rolling an even number or a multiple of 3

On a die:

  • Even numbers = {2, 4, 6}
  • Multiples of 3 = {3, 6}
  • The overlap is {6}

The combined event is {2, 3, 4, 6}.

P(even or multiple of 3) = 4/6 = 2/3

9. Venn Diagrams, Tables and Probability

As probability becomes more complex, diagrams and tables become important tools for organising information.

Representation Best used for
Outcome list Small sample spaces
Outcome table Two-stage experiments such as two dice
Tree diagram Sequential or multistage events
Venn diagram Events that overlap or are mutually exclusive
Two-way table Comparing two categories and calculating probabilities from data

Students should learn to choose a representation that makes the structure of the problem easier to see rather than trying to memorise one method for every question.

10. Conditional Probability and Further Probability

In more advanced probability work, students may consider how knowing that one event has occurred changes the probability of another event. This idea is called conditional probability.

Simple idea

Suppose a card is known to be a picture card. The possible cards are now restricted to the jacks, queens and kings rather than all 52 cards.

Probability is therefore calculated using the new relevant sample space.

Stage 5 extension

Not every student will study the most advanced probability concepts at exactly the same point. NSW Stage 5 pathways can extend Core learning into Further probability, so follow the sequence used by your school and teacher.

11. Theoretical Probability vs Experimental Probability

Theoretical Probability Experimental Probability
Based on mathematical reasoning Based on observed results
Uses known possible outcomes Uses data from trials or simulations
For a fair coin, P(heads) = 0.5 A real experiment might produce 48 heads from 100 tosses
Does not change from trial to trial when the model stays the same Can vary between experiments

12. Common Probability Mistakes

Assuming All Outcomes Are Equally Likely

Before using favourable outcomes divided by total outcomes, check that each basic outcome really has the same probability.

Forgetting the Overlap in an “OR” Question

If A and B can happen together, subtract the overlap so it is not counted twice.

Treating Dependent Events as Independent

If an object is not replaced, the total number of objects and possibly the number of favourable outcomes will change.

Missing Outcomes

Use a table, list or tree diagram for multistage experiments instead of trying to keep every possibility in your head.

Confusing “AND” with “OR”

AND normally means both conditions must be satisfied. OR means at least one of the stated conditions is satisfied.

Giving an Impossible Probability

Every probability must lie between 0 and 1 inclusive. An answer such as 1.25 or −0.3 cannot be a valid probability.

13. A Reliable Method for Solving Probability Questions

  1. Identify the experiment. What exactly is happening?
  2. Identify the event. What outcome or group of outcomes does the question want?
  3. Find or organise the sample space. Use a list, table, Venn diagram or tree diagram if necessary.
  4. Decide whether the events are independent, dependent or overlapping.
  5. Choose the appropriate probability rule.
  6. Simplify the answer and check that it is between 0 and 1.
Exam tip: Show enough working for your method to be clear. A correct diagram, sample space or probability statement can make a multi-step solution much easier to follow and check.

14. Probability in the NSW Mathematics Syllabus

The NSW Mathematics K–10 syllabus groups Years 7–10 learning into Stage 4 and Stage 5. Probability is included in the Stage 4/5 Core, and the course description specifically includes multistage probability. Stage 5 Paths provide extension through Further probability.

Probability learning should also develop the broader NSW Working mathematically processes: communicating, understanding and fluency, reasoning, and problem solving.

For the official syllabus, see the NSW Mathematics K–10 Syllabus .

What this means for students

Do not study probability as a list of disconnected formulas. NSW mathematics increasingly expects students to reason, select an appropriate method, interpret information and explain solutions.

15. What Should Students Practise?

Foundation Core Development More Advanced
Probability scale Complementary events Dependent events
Outcomes and events Experimental probability Without replacement
Sample spaces Two-stage experiments Complex tree diagrams
Simple theoretical probability Independent events Overlapping events
Coins, dice, cards and spinners Outcome tables and tree diagrams Conditional and further probability ideas

Start with the foundation concepts and move forward only when the sample space and basic probability ideas are secure. Most difficult probability questions are built from these same foundations.

Probability Help for NSW Students

Aussie Math Tutor NSW supports students with probability and other Mathematics topics through step-by-step teaching, worked examples and targeted practice.

Face-to-face support is available around Telopea, Oatlands, North Rocks, Dundas, Dundas Valley, Rydalmere, Ermington and Carlingford, with online tutoring available for students across NSW.

If probability feels confusing, the first step is usually to identify whether the difficulty comes from fractions, sample spaces, interpreting the wording of the question, or choosing the correct probability rule.

Explore Years 1–10 Maths Tutoring

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